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Prime or not

This is a discussion on Prime or not within the Java forums, part of the Programming Talk category; This script is a slightly modified version of "Unique Random Numbers". In this script it becomes easier to implement more ...

  1. #1
    insane is offline Junior Member Array
    Join Date
    Apr 2006
    Answers
    16

    Prime or not

    This script is a slightly modified version of "Unique Random Numbers". In this script it becomes easier to implement more than one instances of "Picking Unique Random Numbers".

    This JavaScript picks up a number of unique random elements from an array.

    For example; if you have an array myArray consisting of 10 elements and want to pick 5 unique random elements. Suppose initially myArray[3] is picked randomly, then myArray[3] should not be picked again.

    Code:
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
    <html>
    <head>
    <title>Unique Random Numbers II</title>
    <!--BEGIN HEAD SECTION CODE-->
    <script language="JavaScript">
    // Unique Random Numbers II
    // -Picks a number of unique random numbers from an array
    // By Premshree Pillai
    // http://www.qiksearch.com, http://javascript.qik.cjb.net
    
    function pickNums(nums, numArr, pickArr, count, doFlag, iterations)
    {
     iterations+=1;
     var currNum = Math.round((numArr.length-1)*Math.random());
     if(count!=0)
     {
      for(var i=0; i<pickArr.length; i++)
      {
       if(numArr[currNum]==pickArr[i])
       {
        doFlag=true;
        break;
       }
      }
     }
     if(!doFlag)
     {
      pickArr[count]=numArr[currNum];
      document.write('<b>' + numArr[currNum] + '</b> <font color="#808080">|</font> ');
      /* Modify above line for a different format output */
      count+=1;
     }
     if(iterations<(numArr.length*3)) // Compare for max iterations you want
     {
      if((count<nums))
      {
       pickNums(nums, numArr, pickArr, count, doFlag, iterations);
      }
     }
     else
     {
      location.reload();
     }
    }
    </script>
    </head>
    <!--END HEAD SECTION CODE-->
    <body bgcolor="#FFFFFF">
    
    <!--BEGIN BODY SECTION CODE-->
    <script language="JavaScript">
    var numArr1 = new Array("0","1","2","3","4","5","6","7","8","9"); // Add elements here
    var pickArr1 = new Array(); // The array that will be formed
    var count1=0;
    var doFlag1=false;
    var iterations1=0;
    
    pickNums(5, numArr1, pickArr1, count1, doFlag1, iterations1); // Call the function, the argument is the number of elements you want to pick.
                 // Here we pick 5 unique random numbers
    </script>
    <!--END BODY SECTION CODE-->
    
    </body>
    </html>



  2. #2
    cbdarts is offline Member Array
    Join Date
    Apr 2006
    Answers
    40
    Quote Originally Posted by insane
    This script is a slightly modified version of "Unique Random Numbers". In this script it becomes easier to implement more than one instances of "Picking Unique Random Numbers".

    This JavaScript picks up a number of unique random elements from an array.

    For example; if you have an array myArray consisting of 10 elements and want to pick 5 unique random elements. Suppose initially myArray[3] is picked randomly, then myArray[3] should not be picked again.

    Code:
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
    <html>
    <head>
    <title>Unique Random Numbers II</title>
    <!--BEGIN HEAD SECTION CODE-->
    <script language="JavaScript">
    // Unique Random Numbers II
    // -Picks a number of unique random numbers from an array
    // By Premshree Pillai
    // http://www.qiksearch.com, http://javascript.qik.cjb.net
    
    function pickNums(nums, numArr, pickArr, count, doFlag, iterations)
    {
     iterations+=1;
     var currNum = Math.round((numArr.length-1)*Math.random());
     if(count!=0)
     {
      for(var i=0; i<pickArr.length; i++)
      {
       if(numArr[currNum]==pickArr[i])
       {
        doFlag=true;
        break;
       }
      }
     }
     if(!doFlag)
     {
      pickArr[count]=numArr[currNum];
      document.write('<b>' + numArr[currNum] + '</b> <font color="#808080">|</font> ');
      /* Modify above line for a different format output */
      count+=1;
     }
     if(iterations<(numArr.length*3)) // Compare for max iterations you want
     {
      if((count<nums))
      {
       pickNums(nums, numArr, pickArr, count, doFlag, iterations);
      }
     }
     else
     {
      location.reload();
     }
    }
    </script>
    </head>
    <!--END HEAD SECTION CODE-->
    <body bgcolor="#FFFFFF">
    
    <!--BEGIN BODY SECTION CODE-->
    <script language="JavaScript">
    var numArr1 = new Array("0","1","2","3","4","5","6","7","8","9"); // Add elements here
    var pickArr1 = new Array(); // The array that will be formed
    var count1=0;
    var doFlag1=false;
    var iterations1=0;
    
    pickNums(5, numArr1, pickArr1, count1, doFlag1, iterations1); // Call the function, the argument is the number of elements you want to pick.
                 // Here we pick 5 unique random numbers
    </script>
    <!--END BODY SECTION CODE-->
    
    </body>
    </html>

    VERY interesting, thank you... Except it may have been nicer to make it a blog...

    Chaitanya


  3. #3
    klorpet is offline Member Array
    Join Date
    May 2006
    Answers
    39
    Cool, nice post insane.


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