What is the ouput?

[Adrian]

int main()
{
int i=5;
printf("\n%d",++i + ++i + ++i + ++i + ++i );
}

What will be the result of this code using UNIX OS with CC compiler? Howabout if a TC compiler is used, what will it display? If there is any difference, why is it that way?

[blenda]

Hi,

The answer for both would be the same. The output for the program is 50. It gets executed as follows:
I gets initialized to 5 and then among + and the increment operator ++, the increment operator ++ takes higher priority. And so i get increment as many times as ++ is encountered. So gets incremented 5 times which gives value of i as 10. Then get added five times which results in output 50 to be printed.

Regards,
Blenda

[svs_aditya]

Hi Adrian,

I belive this is the answer for your question.


int main()
{
int i=5;
printf("\n %d", ++i + ++i + ++i + ++i + ++i );
// 6 + 7 + 8 + 9 + 10 =40

printf("\n %d", ++i + ++i + ++i + ++i + i++ );
// 6 + 7 + 8 + 9 + 9 =39

}


So, the preincrement operator works first and then ant other task..... from L to R


regards,
SVS.Aditya