Need Solution

[nura_nkl]

If the distance traveled (s) in time (t) by a partile is given by the formula s = 1+ 2t+3t2+4t3 , then what is the distance travelled in the 4th second of its motion?

[srinugeek]

If the distance traveled (s) in time (t) by a partile is given by the formula s = 1+ 2t+3t2+4t3 , then what is the distance travelled in the 4th second of its motion?

ans:
i think its s4-s3
i e (1+2*4+3*4^2+4*4^3)-(1+2*3+3*3^2+4*3^3)=
2(1)+3(4^2-3^2)+4(4^3-3^3)
2+3*7*1+4*1*(16-12+9)=
2+21+52=(75)

[srinugeek]

hai after rcvng ds ans plz send mail to me