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plzzzzzz solve this puzzles for me.

This is a discussion on plzzzzzz solve this puzzles for me. within the Placement Papers forums, part of the Interviews and Job Listings category; hi plz solve this puzzles for me. 1.if a+b+c+d=d+e+f+g=g+h+i=,...


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  #1 (permalink)  
Old 01-22-2006, 03:37 PM
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bhaskar chakraborty is on a distinguished road
Arrow plzzzzzz solve this puzzles for me.

hi plz solve this puzzles for me.
1.if a+b+c+d=d+e+f+g=g+h+i=,a=4
find d,g.
assume each alphabet takes only one value from one to nine.

Q>if the digit at first place gives the number of one`s,second place no of two`s,third place no of three,.........,ninth place no of nine,tenth place number of zeros.find the number.

plz show the steps in both the problem.
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  #2 (permalink)  
Old 04-03-2006, 12:58 PM
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gathanipratik is on a distinguished road
Thumbs up answer

*** The first question was not correctly written, so I coudn't solve it.

So please send it to me on my email-id.

*** Answer of the second question is

[B] 2100010006[/b]

Answer is self explanatory, there are no steps to explain it. It is reasoning.

All the best...

Have a nice life.
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Old 04-03-2006, 02:13 PM
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roopa2k6 is on a distinguished road
Hi

This problem is like .....
IF A= 4,A+B+C+D = D+E+G+H=G+H+I=17..
whats the value of D and G.


Ans :

(A=4,B=2,C=6,D=5,E=3,F=8,G=1,H=7,I=9)



Try with this u will get the answer....

This is trial and error basis...
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Old 04-04-2006, 03:54 AM
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shreyoshi is on a distinguished road
why cant we solve it like
(A=4,B=3,C=4,D=6,E=4,G=3,H=4,I=10)
If we r using trial and error method we can have multiple results
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Old 05-08-2006, 03:50 AM
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encoder is on a distinguished road
A. if a+b+c+d=d+e+f+g=g+h+i=,a=4
find d,g.

The answer for this problem “if a+b+c+d=d+e+f+g=g+h+i ,a=4; find d and g” is only an expression.

1.) Let’s assume that:
a+b+c+d = x
d+e+f+g = y
g+h+I = z
Therefore a+b+c+d=d+e+f+g=g+h+i is equivalent to x=y=z

Let’s take one of the answers of d and I hope you can solve the rest of the answers.

2.) Let’s subtract both sides by –d so that we get:
a+b+c = x-d from (a+b+c+d-d = x-d)

Why did I do this?
(*)The thing here is that our equation must always be equal even whatever we will do with it. To make it clearer, a direct example will be solve.
In our assumption: a+b+c+d = x, let’s try to set x with the value of 10 and d with value of 1.
From a+b+c+d = x, which is 10 = 10, we have
a+b+c = x-d, which is 9 = 9. This is assuming that a+b+c+d has a value of 10.

3.) After that, we will isolate the d. Doing this is just like doing the procedure of #2.
We then get a+b+c-x = -d.

4.) To get a positive value of d, we will multiply both sides by -1.
We get –a-b-c+x = d or d = x-a-b-c from -1(a+b+c-x) = (-d)-1
The answer is d = x-4-b-c, where 4 is a constant of variable a.

5. Checking the answer if it’s correct. We replace the variables a value.
a = 4, this is constant as given in the problem.
b = 3, c = 2, d = 1

So from a+b+c+d we get 4+3+2+1 = 10 and x is also 10. Therefore 10 = 10
We substitute the given to the answer which is
d = x-4-b-c, => 1 = 10-4-3-2, => 1 = 1

So the solution is:
1.) assume a+b+c+d = x
2.) subtract both sides with d (this is called transposition)
a+b+c = x-d
3.) subtract both sides with x
a+b+c-x = -d
4.) multiply both sides with -1
x-a-b-c = d

The answers:
for d:
d = x-4-b-c
d = y-e-f-g

for g:
g = y-d-e-f
g = z-h-i

Try and solve for the other solutions. Post here my mistakes and I would gladly try to explain it.

For the second question. I can't figure it out because

Last edited by encoder; 05-08-2006 at 03:59 AM.
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Old 05-08-2006, 04:13 AM
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Quote:
If the digit at first place gives the number of one`s,second place no of two`s,third place no of three,.........,ninth place no of nine,tenth place number of zeros. Find the number.
1234567890 or 0987654321
Depending on where you prefer setting the "first place".
But my final answer is 1234567890 because the second answer will have only 987654321 because the 0 will be deleted with common sense.
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Old 05-23-2006, 01:51 AM
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Answer to question 2:

2100010006

Correct. And here's how you do it. The first thing to do is to write the simplest expression of this problem. You have a total of 10 columns each representing a digit and then you need to express how many of each is represented. Start with all zeroes and count them up. So lets put a column at the top and write it as:


1234567890
-----------
0000000000 (but the last column represents the number of 0's, so)
0000000009 (now have one 9, so we have to update it again)
0000000019 (but now there is one less 0 and we have a 1, so)
1000000108 (now we have two 1's and only seven 0's)
2000001007 (but now we have a 2 and one less zero again, so)
2100010006 (and thus you get the answer)

Hope that helps!
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