This is a discussion on plzzzzzz solve this puzzles for me. within the Placement Papers forums, part of the Interviews and Job Listings category; hi plz solve this puzzles for me. 1.if a+b+c+d=d+e+f+g=g+h+i=,...
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hi plz solve this puzzles for me.
1.if a+b+c+d=d+e+f+g=g+h+i=,a=4 find d,g. assume each alphabet takes only one value from one to nine. Q>if the digit at first place gives the number of one`s,second place no of two`s,third place no of three,.........,ninth place no of nine,tenth place number of zeros.find the number. plz show the steps in both the problem. |
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*** The first question was not correctly written, so I coudn't solve it.
So please send it to me on my email-id. *** Answer of the second question is [B] 2100010006[/b] Answer is self explanatory, there are no steps to explain it. It is reasoning. All the best... Have a nice life. |
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A. if a+b+c+d=d+e+f+g=g+h+i=,a=4
find d,g. The answer for this problem “if a+b+c+d=d+e+f+g=g+h+i ,a=4; find d and g” is only an expression. 1.) Let’s assume that: a+b+c+d = x d+e+f+g = y g+h+I = z Therefore a+b+c+d=d+e+f+g=g+h+i is equivalent to x=y=z Let’s take one of the answers of d and I hope you can solve the rest of the answers. 2.) Let’s subtract both sides by –d so that we get: a+b+c = x-d from (a+b+c+d-d = x-d) Why did I do this? (*)The thing here is that our equation must always be equal even whatever we will do with it. To make it clearer, a direct example will be solve. In our assumption: a+b+c+d = x, let’s try to set x with the value of 10 and d with value of 1. From a+b+c+d = x, which is 10 = 10, we have a+b+c = x-d, which is 9 = 9. This is assuming that a+b+c+d has a value of 10. 3.) After that, we will isolate the d. Doing this is just like doing the procedure of #2. We then get a+b+c-x = -d. 4.) To get a positive value of d, we will multiply both sides by -1. We get –a-b-c+x = d or d = x-a-b-c from -1(a+b+c-x) = (-d)-1 The answer is d = x-4-b-c, where 4 is a constant of variable a. 5. Checking the answer if it’s correct. We replace the variables a value. a = 4, this is constant as given in the problem. b = 3, c = 2, d = 1 So from a+b+c+d we get 4+3+2+1 = 10 and x is also 10. Therefore 10 = 10 We substitute the given to the answer which is d = x-4-b-c, => 1 = 10-4-3-2, => 1 = 1 So the solution is: 1.) assume a+b+c+d = x 2.) subtract both sides with d (this is called transposition) a+b+c = x-d 3.) subtract both sides with x a+b+c-x = -d 4.) multiply both sides with -1 x-a-b-c = d The answers: for d: d = x-4-b-c d = y-e-f-g for g: g = y-d-e-f g = z-h-i Try and solve for the other solutions. Post here my mistakes and I would gladly try to explain it. For the second question. I can't figure it out because Last edited by encoder; 05-08-2006 at 03:59 AM. |
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Quote:
Depending on where you prefer setting the "first place". But my final answer is 1234567890 because the second answer will have only 987654321 because the 0 will be deleted with common sense. |
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Answer to question 2:
2100010006 Correct. And here's how you do it. The first thing to do is to write the simplest expression of this problem. You have a total of 10 columns each representing a digit and then you need to express how many of each is represented. Start with all zeroes and count them up. So lets put a column at the top and write it as: 1234567890 ----------- 0000000000 (but the last column represents the number of 0's, so) 0000000009 (now have one 9, so we have to update it again) 0000000019 (but now there is one less 0 and we have a 1, so) 1000000108 (now we have two 1's and only seven 0's) 2000001007 (but now we have a 2 and one less zero again, so) 2100010006 (and thus you get the answer) Hope that helps! |